Official fuel economy ratings for the 2019 Ram 1500 eTorque V6 have been released by the EPA.
New for 2019, the 3.6-liter V6 is mated to an eight-speed automatic and a new 48V mild hybrid system that Ram calls eTorque.
The most efficient version the of engine is in two-wheel drive form, where the 2019 Ram 1500 eTorque V6 is rated at 20 mpg city, 25 highway and 22 combined. For comparison, the 2018 Ram 1500 with the 3.6-liter V6 and two-wheel drive is rated at 17 mpg in the city, 25 on the highway for a combined 20 mpg.
So the highway efficiency didn’t change, but in the city the truck gained 2 mpg.
With 4×4, the eTorque V6 comes in slightly lower at 19 in the city, 24 on the highway and 21 mpg combined. Looking at the 2018 Ram V6 with 4×4, the truck is rated at 16 city, 23 highway and 19 combined.
The 3.6-liter V6 with eTorque is rated at 305 horsepower and 269 lb-ft of torque. The eTorque system can add 90 lb-ft of torque to help the truck get moving from a standstill, but that doesn’t mean the system has 359 lb-ft. That additional power is added at launch and between shifts to help smooth out the power delivery and add just a little more power.
So the bottom line is that eTorque with both the 3.6-liter V6 and the 5.7-liter HEMI V8 is capable of adding a 2 mpg gain. A HEMI V8 with 4×2 is rated at 15 city, 22 highway and 17 combined, while with eTorque the same truck gets 17 city, 23 highway and 19 combined.
Looking at the competition, a Ford F-150 with the base naturally aspirated 3.3-liter V6 is rated at 19 mpg city, 25 on the highway and 22 combined, which means the eTorque is 1 mpg better in the city while also offering more power. The 3.3-liter V6 in the Ford is rated at 290 horsepower and 265 lb-ft of torque.
A full chart of eTorque fuel economy is below.